In number theory, the von Staudt–Clausen theorem is a result determining the fractional part of Bernoulli numbers, found independently by and .
Specifically, if is a positive integer and we add to the Bernoulli number for every prime such that divides , then we obtain an integer; that is,
This fact immediately allows us to characterize the denominators of the non-zero Bernoulli numbers as the product of all primes such that divides ; consequently, the denominators are square-free and divisible by 6.
These denominators are 6, 30, 42, 30, 66, 2730, 6, 510, 798, 330, 138, 2730, 6, 870, 14322, 510, 6, 1919190, 6, 13530, ... .
The sequence of integers is 1, 1, 1, 1, 1, 1, 2, -6, 56, -528, 6193, -86579, 1425518, -27298230, ... .
Proof A proof of the Von Staudt–Clausen theorem follows from an explicit formula for Bernoulli numbers which is:
and as a corollary:
where are the Stirling numbers of the second kind.
Furthermore the following lemmas are needed:
Let be a prime number; then
1. If divides , then
2. If does not divide , then
Proof of (1) and (2): One has from Fermat's little theorem,
for .
If divides , then one has
for . Thereafter, one has
from which (1) follows immediately.
If does not divide , then after Fermat's theorem one has
If one lets , then after iteration one has
for and .
Thereafter, one has
Lemma (2) now follows from the above and the fact that for .
(3). It is easy to deduce that for and , divides .
(4). Stirling numbers of the second kind are integers.
Now we are ready to prove the theorem.
If is composite and , then from (3), divides .
For ,
If is prime, then we use (1) and (2), and if is composite, then we use (3) and (4) to deduce
where is an integer, as desired.H. Rademacher, Analytic Number Theory, Springer-Verlag, New York, 1973.T. M. Apostol, Introduction to Analytic Number Theory, Springer-Verlag, 1976.
See also Kummer's congruence
References
External links